Game 1
Step 1
Per the given scenario, we can write out the five elements to be placed - R, S, T, V, and W, and we can lay out the five positions to be filled in order.
Step 2
Per the second rule, we can create two frames, one with T before both R and S, and the other with T after both R and S.
Step 3
Per the third rule, we can further split each frame into two, one with W before both R and T, and one with W after both R and T.
Step 4
Per the first rule, we can notate in each frame that V must follow S.
Game 2
Step 1
Per the given scenario, we can write out the five elements to be placed - L, M, X, Y, and Z, and lay out the positions to be filled in the Gold room (G) and the Rose room ( R ), solid line positions for 1 pm and 2 pm, and a dashed line for 3 pm, indicating that 3 pm will be in one room or the other, but not both.
Step 2
Per the first rule, notate that M must come before L, and that they must be in the same room.
Step 3
Per the second rule, notate that neither X or Y can come before Z.
Step 4
Per the third rule, notate conditionally that if L is assigned to G, both X and Z must be assigned to R, as well as the contrapositive.
Game 3
Step 1
Per the given scenario, we can write out the five elements to be placed - F, G, I, M, and S - and we can lay out the assignments for the Trents (T), the Williamses (W), and the Yadells (Y). We can indicate that each of them will have at least one assignment for sure, and up to three total.
Step 2
Per the first rule, we can infer and notate that Y can have at most, and thus exactly, one assignment, and W must have at least two assignments.
Step 3
Per the second rule, we can notate that F cannot be grouped with either I or M.
Step 4
Per the third rule, we can notate that either S is assigned to T or I is assigned to Y.
Step 5
We can mark that G is not restricted by any of the rules.
Game 4
Step 1
Per the given scenario, we can write out the five elements to be placed - L, P, R, S and T, and lay out the positions to be assigned in three groups, for bouquets 1, 2, and 3. Each bouquet has 5 slots for up to five assignments, with one slot guaranteed to be filled.
Step 2
Per the second rule, we can notate that the second and third groups have exactly two elements in common.
Step 3
Per the first rule, we can notate that the first and third groups have no elements in common.
Step 4
Per the third rule, we can place S into the third group. We can also infer, per this and the first rule, that S cannot be in group 1.
Step 5
Per the fourth rule, we can notate that if a group has L, it must also have R, as well as the contrapositive.
Step 6
Per the fourth rule, we can also notate that L and S cannot be in a group together. We can also infer, per this rule and the third, that the third group cannot have L.
Step 7
Per the fifth rule, we can notate that if a group has T, it must also have P, as well as the contrapositive.